x^2-2x-4899=0

Solution for x^2-2x-4899=0 equation:

x^2-2x-4899=0

a = 1; b = -2; c = -4899;
Δ = b2-4ac
Δ = -22-4·1·(-4899)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-140}{2*1}=\frac{-138}{2}
=-69
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+140}{2*1}=\frac{142}{2}
=71
$